196x^2+56x+2=0

Solution for 196x^2+56x+2=0 equation:

196x^2+56x+2=0

a = 196; b = 56; c = +2;
Δ = b2-4ac
Δ = 562-4·196·2
Δ = 1568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1568}=\sqrt{784*2}=\sqrt{784}*\sqrt{2}=28\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-28\sqrt{2}}{2*196}=\frac{-56-28\sqrt{2}}{392}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+28\sqrt{2}}{2*196}=\frac{-56+28\sqrt{2}}{392}
$